(1/8)^2^-2n=16

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Solution for (1/8)^2^-2n=16 equation: 



(1/8)^2^-2n=16

We move all terms to the left:

(1/8)^2^-2n-(16)=0

determiningTheFunctionDomain
-2n-16+(1/8)^2^=0

We add all the numbers together, and all the variables

-2n-16+(+1/8)^2^=0

We multiply all the terms by the denominator


-2n*8)^2^-16*8)^2^+(+1=0

Wy multiply elements

-128n^3=0

We do not support enpression: n^3

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